A police jeep is chasing a culprit going on a motorbike. The motorbike crosses the turning at a speed of 72km/h.The jeep follows it at a speed of 90 km/h,crossing the turning ten secs later than the bike. Assuming that they travel at constant speeds, how far from the turning will the jeep catch up the bike

Their displacements will be the same from the turn.

But the jeep starts 10 sec later i.e. 10/3600 hrs later.

S_mb = u_mbt   = 72t

S_jeep = u_jeep (t - 10/3600) = 90(t - 10/3600)       ... since the time taken by jeep will be 10 sec less.

S_mb = S_jeep

72t = 90(t - 10/3600)

t = 1/72 hrs.

Hence the distance = 72x1/72 = 1 km .

So from 1 km from the turn jeek will catch the bike.

Regards,

Team,

TopperLearning.