a police jeep is chasing a culprit, going on a motobike . the motorbike crosses a turning, at a speed of 72 km/hr. the jeep follow it at a speed of 108 km/hr, crossing the turning 10 secsonds later than the bike. assuming that they travel at a constant speeds, how far from the turning will the jeep catch up jeep with the bike.
Asked by PriyaAnk ShaRma
| 16th May, 2013,
10:11: PM
Expert Answer:
Speed of motor bike= 72km/hr = 72x1000/3600 = 20 m/sec
Speed of police jeep = 108 km/hr = 108x1000/3600 = 30 m/sec
Let the jeep catch up the bike after t sec.
At this time the distance travelled by the jeep = speed x time= 30 x t
Distance travelled by motor bike = 20 x (t+10)
At this distance both will be at same position thus equating above values
30t = 20 (t+10)
t= 20 sec.
Thus distance travelled by jeep in 20 sec = 30x20= 600 m
Speed of motor bike= 72km/hr = 72x1000/3600 = 20 m/sec
Speed of police jeep = 108 km/hr = 108x1000/3600 = 30 m/sec
Let the jeep catch up the bike after t sec.
At this time the distance travelled by the jeep = speed x time= 30 x t
Distance travelled by motor bike = 20 x (t+10)
At this distance both will be at same position thus equating above values
30t = 20 (t+10)
t= 20 sec.
Thus distance travelled by jeep in 20 sec = 30x20= 600 m
Answered by
| 23rd May, 2013,
11:43: PM
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