A point charge is placed at the centre of a closed Gaussian spherical 
surface of radius r. Electric flux passing through the surface is Φ. How is 
the electric flux Φ through the surface affected when the following 
changes are made in turn:
(i) The spherical surface is replaced by a cylindrical surface of the 
same radius?
(ii) The point charge is replaced by an electric dipole? Justify your 
answer in each case. 

Asked by shitikanthdas31 | 15th Jun, 2019, 09:58: AM

Expert Answer:

(i) According to the guass law the flux through the closed surface is given byϕ equals q over epsilon subscript 0
The flux due to enclosed charge does not depend on the shape and size of the surface. Therefore the flux would remain same.
 
(ii)
In case of dipole, net charge inside the closed surface is zero. Hence flux will be zero.

Answered by Utkarsh Lokhande | 15th Jun, 2019, 11:10: AM