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A piece of stone of mass 15.1g is first immersed in a liquid and it weighs 10.9gf. Then on immersing the piece of stone in water, it weighs 9.7gf. Calculate:  ( a) the weight of the piece of stone in air, (b) the volume of the piece of stone, (c) the relative density of stone, (d) the relative density of the liquid.
Asked by seemasharma | 21 Dec, 2018, 10:32: PM
Weight in air = 15.1 gf

loss of weight of stone in water = 15.1-9.7 = 5.4gf
hence displaced volume of water = volume of stone = 5.4 cc

relative density of stone = mass/volume = 15.1/5.4 ≈ 2.8

loss of weight of stone in liquid = 15.1 - 10.9 = 4.2 gf

volume of displaced liquid = volume of displaced water = 5.4 c.c
weight of displaced liquid = loss of weight of stone in liquid = 4.2gf

relative density of liquid = mass/volume = 4.2/5.4 = 0.78
Answered by Thiyagarajan K | 21 Dec, 2018, 11:36: PM

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