CBSE Class 11-science Answered
a photon of wavelength 300 nm is absorbed by a gas and then re-emitted as two photons, one photon is red with wavelength 760 nm. The wave number of second photon will be
Asked by Anil | 20 Jun, 2017, 10:45: AM
Expert Answer
E =hc/λ
Wavelength of 1st photon = λ1
Wavelength of 2nd photon = λ2
E(Total) = E1 + E2 = Emitted energy
hc/ λ = hc/ λ1 + hc/ λ2
1/300 = 1/760 + 1/ λ2
1/ λ2 = (1/300 – 1/760)
λ2 = 496 nm = wavelength of second photon
Answered by Vaibhav Chavan | 20 Jun, 2017, 02:04: PM
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