a photon of wavelength 300 nm is absorbed by a gas and then re-emitted as two photons, one photon is red with wavelength 760 nm. The wave number of second photon will be

Asked by Anil | 20th Jun, 2017, 10:45: AM

Expert Answer:

E =hc/λ

Wavelength of 1st photon = λ1

Wavelength of 2nd photon = λ2

E(Total) = E1 + E2 = Emitted energy

hc/ λ  = hc/ λ1  + hc/ λ2 

1/300 = 1/760 + 1/ λ2

1/ λ2  = (1/300 – 1/760)

 λ2   = 496 nm = wavelength of second photon

Answered by Vaibhav Chavan | 20th Jun, 2017, 02:04: PM