a person sitting on the top of a building is dropping ball at regular intervals of one second.find the position of the 3rd,4th,and 5th ball when the 6th ball is being dropped?

Asked by manvendra singh | 19th Nov, 2013, 08:13: PM

Expert Answer:

When the 6th ball is dropped,
 
Time for 6th ball  t = 0 s
               5th ball  t = 1 s
           4th ball t = 2 s
           3rd ball t = 3 s
           2nd ball t = 4 s
           1st ball t = 5 s
 
Now using the equation,
 
s = ut + 1/2 at2      
 
initial velosity for all the balls = 0 m/s
 
S = 1/2 at2         ............................(1) 
 
Now, putting the values of time t for the ball we get the position of each ball accordingly.
 
Position of the 3rd ball (t = 3 s)
 
s = 45 m
 
position of 4th ball  (t = 2 s)
 
s = 20 m
 
position of 5th ball (t = 1 s)
 
s = 5 m
 
 

Answered by Komal Parmar | 20th Nov, 2013, 12:33: PM

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