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Asked by  | 12th Sep, 2008, 04:35: PM

Expert Answer:

let the usual speed of the train = v km/h

then 300 / v = 1 + 300/(v+5)

300(v+5) = v (v+5) + 300v

1500 = v2+5v

v2+5v - 1500 = 0

v= 36.31 or -41.31

since v is positive

so usual spped of train is 36.31 km/h

Answered by  | 12th Sep, 2008, 09:04: PM

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