A passenger arriving in a new town wishes to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest taxidriver takes him along a circuitous path 23 km long and reaches the hotel in 28 minute. What is:

(a) the average speed of taxi

(b) the magnitude of average velocity. Are the two equal?

### Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Magnitude of displacement = 10 km

Total path length = 23 km

Time taken = 28 min = 7/15 hr.

Average speed = distance traveled / time =

### Answered by | 4th Jun, 2014, 03:23: PM

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