Request a call back

A particle which is moving in a straight line with constant acceleration describes distances of 10 m and 15 m in two successive seconds. find the acceleration

Asked by arjunsah797 | 14 Jun, 2021, 06:57: AM
Let u be th initial velocity at nth second .
Then distance S travelled by 1 second interval is determined from the following equation

S = u t + (1/2) a t2  .............................(1)

where a is acceleration

For 1 second interval , let us substitute t = 1 , then we get ,

10 = u + (1/2) a  .........................(2)

For next (n+1)th second , initial velocity is ( u + a )

distance described for a time interval t =1 seconds  at (n+1)th second is determined from eqn.(1) as

15 = (u+a) + (1/2) a  .......................(3)

By solving eqn.(2) and (3) , we get acceleration a = 5 m/s2

Answered by Thiyagarajan K | 14 Jun, 2021, 08:04: AM

Application Videos

CBSE 9 - Physics
Asked by rsaranya658 | 30 Jun, 2022, 02:44: PM
CBSE 9 - Physics
Asked by sanskargunjkar01 | 26 Jun, 2022, 09:13: AM
CBSE 9 - Physics
Asked by poornimaram165 | 21 Jun, 2022, 09:16: PM
CBSE 9 - Physics
Asked by saanidhyapatil | 16 Feb, 2022, 01:23: PM
CBSE 9 - Physics
CBSE 9 - Physics
Asked by debargharoy057 | 25 Sep, 2021, 09:48: AM