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CBSE Class 11-science Answered

A particle travels along a straight line with a velocity of v=(20-o.o5s^2)m/s, where s is in meters. Determine the acceleration of the particle at s=15m.
Asked by Santosh Kumar Singh | 29 May, 2013, 07:01: AM
answered-by-expert Expert Answer
v = 20  - 0.05s2
 
acceleration is given as a = dv/dt = -0.1s.ds/dt
 
where ds/dt = v
 
thus, a = -0.1s.v = -0.1s(20-0.05s2) = -2s + 0.005s3
at s = 15 m
the acceleration would be, a = -30 + 16.875 = -13.125 m/s2
Answered by | 29 May, 2013, 12:56: PM

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