A particle of charge per unit mass alpha is released from origin with a velocity v in positive x axis in a uniform magnetic field B in negative z axis. if the particle passes through (0,y,0) then y is equal to

Asked by ABHISHEK AGARWAL | 24th Aug, 2012, 05:56: PM

Expert Answer:

as the particle passes through the point so it lies on the circular trajectory of the particle and y is the radius:
mv2/y =qvB    .....q/m =alpha=?

Answered by  | 17th Sep, 2012, 03:40: PM

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