A particle is projected vertically upwards.wt will be the ratio of time at 3/4 of its gr8st height?

Asked by  | 12th Jun, 2008, 07:57: PM

Expert Answer:

At greatest height,

t=u/g,h=u2/2g

 

and 3/4 of greatest height,

3/4h=ut' - (1/2)gt'2

on solving, t'=t(/2

or t'/t=0.5

Answered by  | 22nd Jul, 2008, 10:25: PM

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