CBSE Class 11-science Answered
A particle is projected from the ground in vertical direction at t=0 sec.At t=0.8 sec,it reaches h=14m.It will again come to same height at t= ?
Asked by Anaida Ann Rose | 01 Oct, 2012, 11:01: PM
Expert Answer
acceleration actiong on the particle: g = -10 m/ss
t1 = 0.8 s
H = 14 m
let initial velocity be u
thus using the second equation of motion:
H = ut + 1/2gt^2
14 = ut - 5t^2
t1 and t2 be the two solutions
thus t1 = 0.8 s
and t2 = ?
we can solve the equation by first putting in the value of t1 and find u
and then find t2.
Answered by | 01 Oct, 2012, 11:16: PM
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