A particle is moving with constant acceleration. Its displacement and time equation is given as : s=ut+3t.
find (i)the initial velocity
(ii)final velocity after 2 sec
(iii)distance travelled after 2 seconds
I have solved first part and my answer is:
V-6=u
Is it right?
and please tell the answers of other part

Asked by chaitanya | 25th Jun, 2014, 12:34: PM

Expert Answer:

The equation S = ut + 3t seems to be wrong.

Comparing this equation with Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '., we get Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Now, according to the question the particle is moving with uniform acceleration.

Hence, in the equation Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. if a is constant, then t has to be constant to get a constant value as 3.

But, t is not constant and hence the equation is invalid. For the equation to be valid, the equation has to be a quadratic equation in t.

Answered by Romal Bhansali | 3rd Jul, 2014, 10:13: AM