CBSE Class 9 Answered
A particle is moving under constant force it's distance (x) depend on time according to following relations :
t=√x +3, then calculate displacement of particle at that time when it's velocity will be zero?
Asked by shuklaramakant.2016 | 15 Jul, 2022, 07:46: PM
Expert Answer
t = 
+ 3
+ 3 = ( t - 3 )Hence position x at time t is given as
x = (t-3)2 ....................................(1)
velocity v = dx/dt = 2 (t-3) ......................... (2)
we get velocity v = 0 at t =3 from eqn.(2)
Initial position x at t = 0 is obtained from eqn.(1)
at t = 0 , x(0) = 9
position x at t = 3 is obtained from eqn.(1)
at t = 3 , x(3) = 0
displacement S at t = 3 is given as
S = x(3) - x(0) = 0 - 9 = -9
Answered by Thiyagarajan K | 18 Jul, 2022, 08:04: AM
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