a particle is moving in a straight line with initial velocity U and uniform acceleration a. If the sum of the distances travelled in seconds in 100cm , then its velocity after t seconds in cm/s is
Asked by Petulla Mishra | 4th Nov, 2015, 10:16: AM
We know that the distance travelled in nth second of uniformly accelerated motion is:
where u is the initial velocity and a the uniform acceleration of the body.
In this case given that the sum of distances travelled in tth & (t+1)th second is 100 cm.
St + St+1 = 100
If the particle is moving with initial velocity U and uniform accerleration a, then the distance travelled by the particle in tth second can be written as:
Given that St + St+1 = 100
Substituting eqn (1) and (2), we get,
According to the equation of motion, we know that v = u+at, where v is the final velocity, u is the initial velocity, a the acceleration and t the time.
So comparing the equation U+at =50 with the the equation of motion v= u+at, we get that the final velocity of the particle at t second = 50 cm/s.
Answered by Faiza Lambe | 4th Nov, 2015, 11:18: AM
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