A particle is moving along a straight line with a speed V=(0.5t^3-8t)m/s. where t is in seconds. determine the acceleration of the particle when t=2s.

Asked by Santosh Kumar Singh | 29th May, 2013, 06:51: AM

Expert Answer:

Differentiate v to get the acceleration, a.
v = 0.5t3 -8 t
dv/dt =a = 3*0.5*t2 -8
when t=2
a = 1.5 * 22-8
a= 1.5*4-8
a= 6.0 - 8
a=  -2m/s2

Answered by  | 29th May, 2013, 10:23: AM

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