A particle in simple harmonic motion has a position defined by the function x(t) = (80 cm) sin [(20 s-1 )t]. a) Determine the velocity v as a function of time t. b) Determine the acceleration a as a function of time t

Asked by tps.mjmdr | 2nd Jun, 2018, 11:07: AM

Expert Answer:

x(t) = 80×sin[(20s-1)t]
 
velocity dx/dt  = v(t) = 80×(20s-1)cos[(20s-1)t]
 
acceleration dv/dt = a(t) = -80×(20s-1)2sin[(20s-1)t]

Answered by Thiyagarajan K | 4th Jun, 2018, 03:04: PM

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