Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

a particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8 m with one rotation per second. the magnetic field produced at the centre is
Asked by Shashank Shekhar | 26 Jan, 2012, 09:00: PM
answered-by-expert Expert Answer

Here, v=1 rps

R=0.8m

Current due to orbital motion of electron is

I =e/T= ev= 100 x 1.6x 10-19 x1= 1.6 x10-17 A

B= 10-7x 2?I/r

  = 10-7 x2x3.14 x1.6 x10-17/0.8 =12.56 x10-24Wb/m2

Answered by | 27 Jan, 2012, 01:02: AM
CBSE 12-science - Physics
Asked by himanshurawat5823 | 08 Mar, 2024, 01:24: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by rd0543293 | 19 Jun, 2022, 10:51: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by arjunsah797 | 26 Mar, 2022, 09:10: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by arjunsah797 | 16 Mar, 2022, 02:07: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by shantanumail24 | 09 Mar, 2022, 07:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by pushpakumari291279 | 01 Oct, 2021, 11:08: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by yashrajgharte24.12dgatl | 24 Aug, 2021, 07:23: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×