A park in the shape of a quadrilateral ABCD , has angle C =90 , AB=9m , CD=5m , BC=12m and AD=8m.

How much area does it occupy?

 

Asked by firoz.epatra | 23rd Sep, 2019, 09:38: PM

Expert Answer:

In triangle BCD using Pythagoras theorem
BD2 = BC2 + CD2
       = (12)2 + (5)2
       = 144 + 25
BD2 = 169
  BD = 13 m
 
Find area of triangle BCD we get 30 m2
Find area of triangle ABD using Heron's formula we get 35.496 m2 
Area of park = Area of triangle ABD + area of triangle BCD = 65.5 m2 approximately.

Answered by Sneha shidid | 24th Sep, 2019, 09:44: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.