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A park in the shape of a quadrilateral ABCD , has angle C =90 , AB=9m , CD=5m , BC=12m and AD=8m.

How much area does it occupy?

Asked by firoz.epatra | 23 Sep, 2019, 09:38: PM
In triangle BCD using Pythagoras theorem
BD2 = BC2 + CD2
= (12)2 + (5)2
= 144 + 25
BD2 = 169
BD = 13 m

Find area of triangle BCD we get 30 m2
Find area of triangle ABD using Heron's formula we get 35.496 m2
Area of park = Area of triangle ABD + area of triangle BCD = 65.5 m2 approximately.
Answered by Sneha shidid | 24 Sep, 2019, 09:44: AM

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