A parallel plate capacitor is immersed in a liquid dielectric constant[k].find the force acting
Asked by | 4th Apr, 2008, 12:46: AM
Electric field due the capacitor is given by E=(σ/ε0) n cap.
Now force on the conductor is force= sigma multiply by average electric field.
so force =(1/2 multiply byσ/ε0) multiply by σ2. n cap.
now if we introcude the dieletric "k", then ε0 will multiply by "k" in above equation.
Answered by | 4th Apr, 2008, 05:51: PM
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