A parallel plate capacitor is immersed in a liquid dielectric constant[k].find the force acting

 

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Electric field due  the capacitor is given by   E=(σ/ε₀) n cap.

 

Now force  on the conductor is force= sigma multiply by average electric field.

so force =(1/2 multiply byσ/ε₀) multiply by σ². n cap.

now if we introcude the dieletric "k", then ε₀ will multiply by "k" in above equation.