A parallel plate capacitor is charged by a dc source to potential V.Without disconnecting the capacitor form the source,air is replaced by another dielectric medium of dielectric constant 10.State with reasons how
1)electric field between the plates
2)energy stored in the cpacitor change

Asked by Malavika Umesh | 22nd May, 2014, 12:19: PM

Expert Answer:

1. In present case, the air is replaced by another dielectric medium of dielectric constant 10 without disconnecting the capacitor from the d.c source, hence potential difference between the plates of capacitor remains unchanged. Consequently, electric field between the plates Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. remains unchanged.
2. Now capacitance of capacitor Cm = K C = 10 C
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Thus, energy stored becomes 10 times the value with air as dielectric.

Answered by Faiza Lambe | 27th May, 2014, 12:06: PM