A NUCLEUS WITH A=240 HAS A BINDING ENERGY OF 7.5MeV PER NUCLEON. WHEN IT SPLITS INTO TWO FRAGMENTS OF EQUAL MASS, 240MeV OF ENERGY IS RELEASED. THE BINDING ENERGY PER NUCLEON OF DAUGHTER NUCLEI IS:

Asked by simi | 10th Feb, 2012, 05:12: PM

Expert Answer:

The energy released= (2x 120x EbN -240x 7.5)
 
240 Mev=( 2x 120xEbN- 240X7.5)
 
SOLVE THE EXPRESSION AND GET THE BINDING ENERGY PER NUCLEON IN Mev.

Answered by  | 11th Feb, 2012, 07:22: PM

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