A nucleus Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. undergoes β- decay and becomes Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '., Calculate the maximum kinetic energy of electrons emitted assuming that the daughter nucleus and anti- neutrino carry negligible kinetic energy.

Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Asked by Topperlearning User | 9th Jul, 2014, 12:48: PM

Expert Answer:

β- decay of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. is given as:

Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Where,

Q = kinetic energy of the daughter nucleus Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Ignoring the rest mass of the anti-neutrino Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.and the mass of the electron Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.,

the mass defect involved in the nuclear reaction is given as:

Δm = mSyntax error from line 1 column 58 to line 1 column 82. Unexpected '<mstyle '. -m Syntax error from line 1 column 58 to line 1 column 82. Unexpected '<mstyle '.

      = 22.994466 - 22.989770

      = 0.004696 u = 0.004696 x 931.5 MeV/c2 = 4.374 MeV/c2

therefore Q = Δ mc2 = 4.374 MeV

Hence, when the energy carried by Syntax error from line 1 column 56 to line 1 column 97. Unexpected '<mi '. is zero, the maximum kinetic energy of β particle is 4.374 MeV.

Answered by  | 9th Jul, 2014, 02:48: PM