A neutron is absorbed by a 3 L nucleus with subsequent emission of - particle Write the corresponding nuclear reaction. Calculate the energy released in this reaction.
Given mass of 3 L = 6.015126 a.m.u.
Mass of 2e = 4.000 26044 a.m.u.
Mass of neutron = 1.0086654 a.m.u.
Mass of tritium = 3.016049 a.m.u.
Asked by Topperlearning User | 2nd Jun, 2015, 10:23: AM
Nuclear reaction is given by
Mass of reactants = m
= 1.0086654 + 6.015126 = 7.0237914 a.m.u.
Mass Defect, Δm = mass of reactant - mass of product.
Δm = 7.0237194 - 7.0186534
Δm = 0.005138 a.m.u.
Since1. a.m.u. = 931 MeV
Energy released =Δm x 931 MeV
E = 0.005138 x 931
|E = 4.783MeV|
Answered by | 2nd Jun, 2015, 12:23: PM
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