A monkey of mass 40kg climbs up a rope of breaking load 600N hanging from a ceiling.if it climbs up the rope with maximum possible acceleration,then find the time taken by the monkey to climb up(length of the rope 10m) (a)2secs (b)1secs (c)3secs (d)4secs

Asked by  | 30th Mar, 2013, 10:14: AM

Expert Answer:

Mass of the monkey, m = 40 kg

Acceleration due to gravity, g = 10 m/s

Maximum tension that the rope can bear, Tmax = 600 N

Using Newton’s second law of motion, we can write the equation of motion as:

T – mg = ma

?T = m(g + a)

600 = 40(10+a)
a =5m/s2
 time taken by the monkey to climb up(length of the rope 10m.
s =ut + 1/2 at
10 = 0xt +1/2 X5 xt2
t2 = 4
t= 2 sec
 
 

Answered by  | 30th Mar, 2013, 11:25: AM

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