A metal forms two oxides. The higher oxide contains 80% metal. 0.72 g of of the lower oxide gives 0.8g of the higher oxide when oxidized. Illustrate using the law of multiple proportions

 

In higher oxide

 

Wt of metal= 0.8x80/100=0.64g

 

Wt. Of oxygen=0.8-0.64=0.16g

 

In lower Oxide

 

Wt. of metal will remain the same as in higher oxide=0.64g

wt. of oxygen =0.72-0.64=0.08g

 

The ratio of weight of oxygen which combines with a fixed weight of metal in two oxides is

 

0.16:0.08

2:1

As it is a whole number ratio . The law of multiple proportion is illustrated.