CBSE Class 11-science Answered
A mass of 8 kg is suspended by a rope of length 4 m from the ceiling. A force of 40 N in the horizontal direction is applied at the midpoint P of the rope, as shown in the figure below. What angle does the rope make with the vertical in equilibrium?
Asked by Topperlearning User | 05 Jun, 2014, 05:22: PM
Expert Answer
From the figure, we have
T2 = 8 × 10 = 80 N
Now, considering the equilibrium of the point P under the action of three forces, T1, T2
and horizontal force 40 N, the horizontal and vertical components of the resultant forces
must vanish separately.
T1cos θ = T2 = 80 N
T1 sin θ = 40 N
By dividing the above two equations, we get
Answered by | 05 Jun, 2014, 07:22: PM
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