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CBSE Class 10 Answered

a man's property of 19000 rupees is divided between his wife ,3 sons and 2 daughters.the wife gets twice of what each son gets and thrice of what each daughter gets.what is each daughter's share?
Asked by Ashrene | 26 Oct, 2012, 05:39: PM
answered-by-expert Expert Answer
Answer : Given : a man's property of 19000 rupees is divided between his wife ,3 sons and 2 daughters.the wife gets twice of what each son gets and thrice of what each daughter gets.
To find : each daughter's share
 
Let each son get x Rs each and each daughter recieves y Rs each. 
 
According to the question, the wife receives twice the share to each son , and thrice of each daughter gets, therefore the sum that wife receives is :
=> 2x = 3y .........................(1)
 
and 
 
total sum is :
wife's sum + 3 son's sum +  daughter's sum = 19000
=> 2x + 3x + 2y =  19000
=> 5x + 2y = 19000
=> 5x + 2(2/3)x =19000   {using eq 1}
=>15x + 4x = 3 * 19000
=> 19 x = 3 *19000
=> x = 3000 Rs 
 
Now using the value of x in eq 1 , e get 
=> y = (2/3) x = 2000 Rs 
 
 
Answer : Each daughter receives a sum of Rs 2000.
Answered by | 26 Oct, 2012, 06:42: PM

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