a man whose bowling average is 12.4 takes 5 wickets for 26 rus and therby decreases his average by 0.4. the numbe of wickets taken by him before his last match is??

Asked by devangi meena | 8th Dec, 2013, 06:24: PM

Expert Answer:

Suppose the man has taken x wickets before his last match.
His average before the last match = 12.4
His total before the last match = 12.4 x x runs
Thus, his total wickets = 12.4x + 26       ... (1)
 
Now, his reduced average for (x+5)wickets = 12.4-0.4 = 12
His total for (x+5) wickets = 12 (x + 5)      ... (2)
From (1) and (2),
12.4x + 26 = 12(x+5)
On solving, we get x = 85.
Hence, the man has taken 85 wickets before his last match.

Answered by  | 8th Dec, 2013, 07:12: PM

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