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A man weighing 50 kg f supports a body of 25 kg f on his head. What is the work done when he moves a distance of 20 m up an incline of 1 in 10? Take g = 9.8 m/s2
Asked by | 01 Sep, 2012, 08:45: AM
and incline of one in 10 means that in moving 20 m he reached a height of H= 2 m.
total weight of man and block = 75kg
thus work done is: mgH
75*9.8*2 = 1470J
Answered by | 01 Sep, 2012, 10:24: AM

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