Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

a man buys x no of article for 1200 .10 were broken .he sold the rest at 2 rs profit.thus gaibging rs 60 on whole transaction .find x
Asked by rahul raj | 20 Feb, 2011, 11:38: PM
Expert Answer
dear student,
the cost of each aarticle 1200/x
10 were broken,
so now,
 no. of articles =x-10
s p of each article
=(1200/x) +2
so S P  of x-10 articles= (x-10) x S P  of each article
so ATQ,
(x-10)[(1200/x)+2]=1260
2-8x-12,000=0
solving we get,
(x-100)(x+60)=0
x=100
chk-
C.P. of each article=12 Rs.
no.of articles left=100-10=90
S.P. of each article= 12+2=14
total SP
=90 x 14=1260
so total SP
1260-1200
=60
answer chkd
Answered by | 21 Feb, 2011, 01:52: PM
CBSE 10 - Maths
Asked by devchauhan25007 | 17 Jul, 2022, 04:29: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by rajendrame089 | 28 Jun, 2022, 07:09: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by gurjaeharsh | 16 Jun, 2022, 01:11: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by atharvsharma971 | 06 Jun, 2022, 10:30: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by harshitpranjalraj24 | 03 Jun, 2022, 09:33: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by zk4656260 | 31 May, 2022, 05:32: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by s.kmounesha | 23 May, 2022, 02:35: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ankur.spsharma | 02 May, 2022, 11:54: AM
ANSWERED BY EXPERT
×