A light of wavelength 3 × 10 ^- 7 strikes a metal surface. the energy of incident light in electron volt is

Asked by arushidabhade | 13th Aug, 2019, 01:31: PM

Expert Answer:

Given
 
Wavelength, λ = 3×10−7 m
 
We know,
 
Energy, E 
 
 
equals hc over straight lambda

equals fraction numerator 6.636 cross times 10 to the power of negative 34 end exponent cross times 3 cross times 10 to the power of 8 over denominator 3 cross times 10 to the power of negative 7 end exponent end fraction

equals 6.6 cross times 10 to the power of negative 19 end exponent space straight J
 
1 eV = 1.6 × 10−19 J
 
6.63× 10−19 J = 4.14 eV

Answered by Varsha | 13th Aug, 2019, 04:16: PM