A lift whose cage is 3 m high is moving up with an acceleration of 2m/s2. A piece of stone is dropped from the top of the cage of the lift when its velocity is 8m/s. if g =10m/s2 then the stone wil reach the floor of the lift after how much time?
A lift whose cage is 3 m high is moving up with an acceleration of 2m/s2. A piece of stone is dropped from the top of the cage of the lift when its velocity is 8m/s. if g =10m/s2 then the stone wil reach the floor of the lift after how much time?
Asked by Saptarshi Sen | 19th Apr, 2015, 02:01: PM
Expert Answer:
Given that:
a = 2 m/s2, s =3m,
The lift is accelerated frame of reference and the effective downward force on the stone is (a+g).
Since, the stone is at rest with respect to the moving cage, its initial velocity is 0
Thus the stone will reach the floor of the lift in 7s.
Answered by Yashvanti Jain | 13th Dec, 2017, 06:28: PM
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