A large stone

Asked by  | 20th Mar, 2013, 02:26: PM

Expert Answer:

we know that 

weight of water displaced = weight of iceberg plus stone

so,

?wVg = Mg

here, M = mass of iceberg + 300kg = (m+300) kg

thus,

?wVg = (m+300).g

m + 300 = ?wV = 1020 x V

so,

m = 1020.V - 300

here,

V = total volume of iceberg = mass of iceberg / density of iceberg = m/?i

thus,

m = 1020x(m/?i) - 300

m - 1020x(m/920) = -300

so,

0.108m = 300

thus, mass of iceberg will be

m = 2777.8kg

 

Answered by  | 20th Mar, 2013, 05:09: PM

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