CBSE Class 9 Answered
A large stone
Asked by | 20 Mar, 2013, 02:26: PM
Expert Answer
we know that
weight of water displaced = weight of iceberg plus stone
so,
?wVg = Mg
here, M = mass of iceberg + 300kg = (m+300) kg
thus,
?wVg = (m+300).g
m + 300 = ?wV = 1020 x V
so,
m = 1020.V - 300
here,
V = total volume of iceberg = mass of iceberg / density of iceberg = m/?i
thus,
m = 1020x(m/?i) - 300
m - 1020x(m/920) = -300
so,
0.108m = 300
thus, mass of iceberg will be
m = 2777.8kg
Answered by | 20 Mar, 2013, 05:09: PM
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