CBSE Class 11-science Answered
a jet plane speed 500km/hr ejects product of combustion at the speed of 1500Km/hr relative to plane what is the speed of the latter with respect to an observer on ground.
Asked by | 24 Sep, 2010, 12:00: AM
Expert Answer
Velocity of combustion products w r t plane =
Velocity of combustion products w r t observer on ground - Velocity of plane w r t observer on ground.
1500 = Velocity of combustion products w r t observer on ground - 500
Velocity of combustion products w r t observer on ground = 2000 km/hr.
Regards,
Team,
TopperLearning.
Answered by | 25 Sep, 2010, 12:09: AM
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