a jet plane speed 500km/hr ejects product of combustion at the speed of 1500Km/hr relative to plane what is the speed of the latter with respect to an observer on ground.

Asked by  | 24th Sep, 2010, 12:00: AM

Expert Answer:

Velocity of combustion products w r t plane =
Velocity of combustion products w r t observer on ground - Velocity of plane w r t observer on ground.
1500 = Velocity of combustion products w r t observer on ground - 500
Velocity of combustion products w r t observer on ground = 2000 km/hr.
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Answered by  | 25th Sep, 2010, 12:09: AM

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