CBSE Class 11-science Answered
A jet airplane traveling at the speed of 500 km/hr ejects its products of combustion at the speed of 1500 km/hr relative to the jet plane. What is the speed of the later with respect to an obserever on the ground?
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
Let Vg be the velocity of ejecting gases with respect to ground.
velocity of jet plane Vj = + 500 km/hr
Velocity of ejected products w.r.t. jet plane
Vgj = Vg - Vj
or, Vg = Vgj + Vj
= -1500 + 500 = -1000 km/hr
Answered by | 04 Jun, 2014, 15:23: PM
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