A is elder to B by 2 yrs.A's father F is twice as old as A nd B istwice as old as his sister S.if the ages of da father nd sister differ by 40 yrs,find da age of A.

Asked by  | 17th Aug, 2011, 12:00: AM

Expert Answer:

Let age of A be A years,
      age of B be B years
      age of F be F years
        age of S be S years
ATQ,   A = B + 2      ........(1)
            F = 2A          ......(2)
            B = 2S          ........(3)
            F - S = 40    ........(4)
Substituting equations (2) & (3) in (4),
2A - B/2 = 40
=>  4A - B = 80      .........(5)
Solving eqn (1) & (5), we get
        3A = 78
=>   A = 26

Answered by  | 17th Aug, 2011, 03:35: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.