a) Identify the substance oxidised, substance reduced, oxidising agent and reducing agent in the following reaction:
b) In the reaction , what is oxidised and what is reduced?
Asked by adalroshan2464
| 12th May, 2019,
03:19: PM
Expert Answer:
(a) In this reaction, We need to find oxidation numbers in each compound
In MnO2,Oxidation number of Mn will be x-4=0
x=+4
In MnCl2,Oxidation number of Mn will be x-2=0
x=+2
So from conversion to MnO2 to MnCl2, Oxidation number is reduced which means MnO2 is reduced to MnCl2 and this process is reduction.
MnO2 is reduced so it will oxidise other compounds.
So MnO2 =Oxidising agent
When HCl is converted to Cl2, it looses hydrogen so when hydrogen is released it means this is Oxidation process and HCl is oxidised which means it will reduce other compounds
So HCl=Reducing agent
(b)
Zn is oxidised in ZnSO4 and CuSO4 is reduced in Cu.


Answered by Ravi
| 14th May, 2019,
12:28: PM
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