a hot air balloon is rising up with a speed of 10 meter per second.when it is at o height of 100m a packet is dropped from the balloon .after how much time and with what velocity does it reach the ground

Asked by Ankita Gupta | 24th May, 2012, 05:56: PM

Expert Answer:

S = ut+ 1/2 at2
 
100 = 0 + 1/2 * 10 *t2
 
20 sec = t2
 
from this equation we can find the time taken to reach the ground
 
v2 - u2 = 2aS
 
v2 - 0 = 2 * 10 * 100
 
v2 = 2000 m/s
 
from this equation , we can find the final velocity
 

Answered by  | 25th May, 2012, 12:53: PM

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