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CBSE Class 9 Answered

A hemispherical metal bowl has thickness 0.21 cm. The inner radius of the bowl is 7 cm. Find the outer curved surface area of the bowl.
Asked by Topperlearning User | 18 Oct, 2017, 03:07: PM
answered-by-expert Expert Answer

Given inner radius = 7 cm, thickness = 0.21 cm

⇒ Outer radius (r) = 7 cm + 0.21 cm = 7.21 cm

Let S be the outer curved surface area of the bowl.

 

begin mathsize 12px style straight S space equals space 2 πr squared straight S space equals space 2 cross times 22 over 7 cross times 7.21 cross times 7.21 straight S space equals space 326.7572 space cm squared end style


 

Curved surface area of the bowl is 326.7572 cm2


Answered by | 18 Oct, 2017, 05:07: PM

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