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CBSE Class 11-science Answered

A.  give method and find hybridisation and shape of : 1. XeF2 2.SF2 3.I I to the power of negative 2 end exponent 4.IF7 5.SO subscript 4 superscript negative 2 end superscript B.Explain anti bonding and bonding hybridised orbitals. C._________on hydrolysis gives ethyne while ______ on hydrolysis gives methane. D.Explain why the colour of Bayer's reagent gets discharged when treated  with an alkene. E.i) State and explain Le Chatelier’s principle. On the basis of this principle discuss the conditions for obtaining the maximum yield of SO3 in the following reaction. 2SO2(g)+ O2(g)⇌2SO3(g); ∆𝐻= - 42k.cal.(ii) Calculate the pH value of 0.01M CH3 COOH if it is 5% dissociated.
Asked by defence | 17 Feb, 2020, 05:09: PM
Expert Answer

Que: Explain anti bonding and bonding hybridised orbitals.

 
Ans:  When two atomic orbitals overlap, they interact to form two molecular orbiotals. One is bonding molecular orbital
and other is antibonding molecular orbital.
The bonding molecular orbital has lower enrgy and hence the greater stability than corresponding antibonding molecular orbital.
 
 
Que: CaCon hydrolysis gives ethyne while Al4C3 on hydrolysis gives methane.
 
Reaction: 
 
CaC2 + H2O → Ca(OH)2 + C2H2 
 
Al4C3  + 6H2O → 2Al2O3 + 3CH4 
Answered by Varsha | 18 Feb, 2020, 05:09: PM
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