CBSE Class 9 Answered
a girl having a mass of 35kg sits on a trolley of mass 5 kg. the trolley is given an initial velocity of 4m/s by applying a force. the trolley comes to rest after travelling a distance of 16m. how much work is done on the trolley? how much work is done by the girl?
Asked by Saranya Krishnamurthy | 15 Feb, 2014, 04:43: PM
Expert Answer
Given:
Mass of girl = 35 kg
Mass of trolley = 5 kg
Total mass, m = (35 + 5) = 40 kg
u = 4 m/s
v = 0
s = 16 m
By equation,
v 2 = u 2 + 2as
0 = (4)2 + 2a (16)
32a = –16
a = –0.5 m/s2
Force exerted on trolley,
F = ma
= 40 × 0.5 = 20 N
Work done on trolley W = FS = 20 N x 16 m
= 320 J
Work done by the girl, W = FS
= mass of girl × retardation × S
= 35 × 0.5 × 16
= 280 J
Answered by | 17 Feb, 2014, 09:07: AM
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