a gas mixture of 3L of propanone and butane on combustion at 25 degree celsius produced 10L of co2. find out the composition of gas mixture?

Pure 1L Propane yeilds 3L CO2

Pure 1L Butane yeilds 4L CO2

So mixture of both the gase should be in 2: 1 ratio to yeild 10 L CO2

It means 2L of Propane and 1 L of Butane

  CO2 will be yeild 2 * 3L + 4L = 10 L