A furnace emits radiation at 2000 K. Treating it as a black body radiation, calculate the monochromatic radiant flux density at 1 micron m wavelength

Asked by prabhakararao viriyala | 14th Jun, 2020, 12:17: PM

Expert Answer:

C subscript 1 equals space 0.374 cross times 10 to the power of negative 15 end exponent space W m squared
c subscript 2 space equals space 1.43 space cross times 10 to the power of negative 2 end exponent space m K
lambda equals 1 cross times 10 to the power of negative 6 end exponent space m space
B y space P l a n c k apostrophe s space l a w space o f space d i s t r i b u t i o n comma space
open parentheses E subscript lambda close parentheses subscript b space equals space fraction numerator c subscript 1 lambda to the power of negative 5 end exponent over denominator e to the power of open parentheses begin display style fraction numerator c subscript 2 over denominator lambda T end fraction end style close parentheses end exponent minus 1 end fraction space equals space fraction numerator 0.374 cross times 10 to the power of negative 15 end exponent cross times open parentheses 1 cross times 10 to the power of negative 6 end exponent close parentheses to the power of negative 5 end exponent over denominator e x p open square brackets open parentheses 1.43 cross times 10 to the power of negative 2 end exponent close parentheses divided by 1 cross times 10 to the power of negative 6 end exponent cross times 2000 close square brackets minus 1 end fraction equals fraction numerator 0.374 cross times 10 to the power of 15 over denominator 1331.4 minus 1 end fraction space
equals space 2.81 cross times 10 to the power of 7 W divided by m squared

Answered by Shiwani Sawant | 15th Jun, 2020, 09:26: PM