A frictionless track ends in a circular loop of radius R.A body slides down the track from a point A which is at a height 5cm .Max value of R for the body to successfully complete a loop?

Asked by  | 28th Mar, 2013, 12:24: PM

Expert Answer:

mgh=PE at h
mgh=1/2 mv2 =KE at B
at B=1/2 mv2=mg(2R)...energy conservation law applied in circular loop
mgh=1/2 mv2
mgh=(1/2) m 4R
R max=gh/2

Answered by  | 15th Apr, 2013, 04:36: PM

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