A force of 100N acts on an object of mass 10kg for 9seconds. If the object was initially moving with the speed of 10m/s, calculate the initial and final kinetic energy of the object.By what factor does the kinetic energy increase?
Asked by rajinderkaur1528 | 8th Feb, 2019, 03:28: PM
Expert Answer:
F = 100 N, m = 10 kg, t = 9 s, u = 10 m/s, Initial kinetic energy - K.E.i = ?, Final kinetic energy K.E.f = ?
u = 10 m/s,
Thus, K.E.i = 1/2 × m × u2 = 1/2 × 10 × 102 = 500 J
F = m x a
a = F/m = 100/10 = 10 m/s2
v = u + at
v = 10 + (10) x 9
v = 100 m/s
K.E.f = 1/2 × m × v2 = 50000 J
Factor by which the kinetic energy increases,
Answered by Shiwani Sawant | 8th Feb, 2019, 05:10: PM
Concept Videos
- ex. 2c q 6
- ex. 2c q 5
- exercise 2b q 24
- exercise 2c q6
- exercise 2c q5
- q14
- what exactly is gravitational potential energy? is it the potential energy of the force of gravity or the potential energy against the force of gravity?
- What is kinetic and potential energy?
- A body of mass m is moving with velocity v. Write the expression for its kinetic energy.
- A solid metal weighing 150 g melts at its melting point of 800 degree C by providing heat of 100 W. The time taken for it to completely melt at the same temperature is 4 min. What is the specific latent heat of fusion of the metal ?
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change