A force acting on a body of mass 2 kg moves it, such that its position y as a function of time is given by the relation y=t^3/3; where y is in meter and t is in sec. Calculate the work done by the force in the first two second.

Asked by Yash Mishra | 5th Nov, 2013, 06:56: PM

Expert Answer:

Answered by  | 10th Nov, 2013, 10:25: PM

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