A fish is raising vertially to the surface of water in a lake uniformly at the rate of 2m/s observes a bird diving vertically towards water at a rate of 4m/s vertically above it.the refractive index of water is 4/3.what is the actual velocity of the bird?

Asked by  | 21st Nov, 2012, 06:15: PM

Expert Answer:

Ans. 1.5m/s
If at any instant the fish is at the depth 'x' below fish water surface while the bird at a height y above the surface, then the apparent height of the bird from the surface as seen by the fish will be given by
µ =  or Apparent height = µy
So, the total apparent distance of the bird as seen by the fish in water will be
h = x + µy
or 
         4= 2 + µ()
dy/dt =2/(4/3)=6/4=3/2=1.5m/s

Answered by  | 22nd Nov, 2012, 01:08: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.