A drop of mercury of radius 3 mm splits into 27 identical droplets. Find the increase in surface energy. Surface tension of mercury is 0.465 N/m.

Asked by Topperlearning User | 1st Aug, 2014, 04:23: PM

Expert Answer:

Let r be the radius of the small droplet. As the volume of mercury will remain constant on splitting the drop into droplets, therefore

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Answered by  | 1st Aug, 2014, 06:23: PM